9x^2+101x+260=0

Solution for 9x^2+101x+260=0 equation:

9x^2+101x+260=0

a = 9; b = 101; c = +260;
Δ = b2-4ac
Δ = 1012-4·9·260
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-29}{2*9}=\frac{-130}{18}
=-7+2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+29}{2*9}=\frac{-72}{18}
=-4
$